$+4+5-8+2-9+4-8+\left(-6\right)$
$11=m-4$
$\frac{-2x}{3}+6\le\frac{-8x}{5}-4$
$\int\frac{1}{\left(x+1\right)^2+2}dx$
$a^3-5a^2-4a$
$\int_2^6xdx$
$m+6^2$
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