$3a^2-3a-6$

$6\sqrt[3]{m}-10\sqrt[3]{m}$

$\int x\left(x^2-3\right)xdx$

$\left[\left(-10\right):\left(5\right)\right]\left[\left(-16\right):\left(+2\right)\right]$

$\left(a^3-4\right)\left(a^6+4a^3+16\right)$

$\int\left(x-5\right)^{3}dx$

$\left(-2s^2\:+\:4s\:-\:10\right)$