$y'+xy=2$
$x\frac{dv}{dx}=\frac{4v^3}{1+4v^2}$
$2x\cdot6xy$
$\left(5y^2+14\right)\left(5y^2-14\right)$
$-31\:+\:-982\:=\:$
$\left(3xy-5x\right)^3$
$15x^2-4x-4$
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