$18-\left(-15\right)-6-5+0$
$2\cdot8-10$
$y'=-3x^2y$
$5x^2+13x+12=0$
$\lim_{x\to\infty}\left(\frac{\arctan\left(x^2\right)}{x^2-2}\right)$
$\left(4+x^8\right)\frac{dy}{dx}=\frac{x^7}{y}$
$\int\frac{9}{\left(6x-1\right)x}dx$
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