$\left(10st-s^2v^3\right)^2$
$\int\frac{\sqrt{324+x^2}}{x}dx$
$-3-5+\left(-8\right)-1-\left(-3\right)+1-8$
$34j^2+92j=0$
$\int x^{m+1}dx$
$\frac{\left(2-3x\right)}{\left(2x^{2\:}-3x+1\right)}$
$\left(3q-12p\right)^{2}$
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