$\frac{8x^2+6x+4}{x+2}$
$2^5+5-3^3$
$-22+\:2$
$f\left(x\right)=\tan\left(x\right)\cdot\csc\left(x\right)$
$\left(\frac{a^5c^4d^3}{b^4}\right)\left(\frac{d^6}{c^9}\right)$
$\left(2v-10\right)\left(-v+10\right)$
$\left(4x^2\right)\left(2x^3-4\right)$
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