$\lim_{x\to\infty}\left(\frac{\left(\frac{\left(x^2-x-2\right)}{x-5}\right)}{x}\right)$

$\left(2^7\cdot4^{-4}\right)\left(3^{-5}\cdot4^{-4}\right)$

$\frac{x\le3\left(-2x+3\right)}{8}-\frac{5\left(1-x\right)}{6}$

$4m+3y+14m+16y$

$\int\left(t^3\left(t^4-3\right)^3\right)dx$

$\frac{2}{\cot\left(z\right)-\tan\left(z\right)}=\tan\left(2z\right)$

$96z^2+144z$