$s^2+13s+10$
$\frac{\cos\left(8x\right)+\cos\left(6x\right)}{\sin\left(8x\right)-\sin\left(6x\right)}$
$\frac{16a^9b^7}{\left(2a^3b^2\right)^3}$
$5^6\cdot\frac{5^4}{5^2}\cdot\frac{5^8}{\cdot5}$
$-10=91-x$
$80+212$
$\left(6x\:-\:12\right)\left(6x\:+\:12\right)$
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