$4x-7<3x+4$
$12x\:-\:4\:+\:x\:-\:2$
$6x^2-9x-8xy+12y$
$x^4+2x^3+x^2-4$
$5x-3>9$
$7\left(x^2+2\right)-5x^3+x-1-\left(x+3\right)\left(x-1\right)$
$\int tan^2\frac{5x}{3}sec^4\frac{5x}{3}dx$
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