$\left(4x^3-y^2\right)\left(4x^3-y^2\right)$
$x2+4=8$
$\int\left(x^3+1\right)\left(2x^4+8x\right)^4dx$
$\left(\frac{x^{-2}y^4\cdot2y^3}{\left(2y^3\right)^{-1}}\right)^3$
$m+5\cdot m+3$
$65\cdot5$
$\frac{-25a^{12}b^9}{-5a^66^3}$
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