$\lim_{x\to-3}\left(\frac{x^2-4x+3}{x-3}\right)$

$-11m+7m-4m-_{-10}$

$-x^3-15x^2-15x-125$

$\sqrt{x^3+\frac{1}{x^3}+3\left(x+\frac{1}{x}\right)}$

$\frac{\left(-2p^2\right)^4\left(3p^4\right)^2}{\left(-6p^3\right)^2}$

$2\:cos\:360\:-3\:tg\:135\:+\:cotg\:225$

$\int\frac{\left(\arctan\left(8x\right)\right)^2}{64x^2+1}dx$