$\sin\frac{x}{2}=0$
$\frac{x^3+4x^2+5x+2}{x+1}$
$\frac{\left(1\right)}{x\cdot\left(\left(x^2\right)-16\right)}$
$\left(-23\right)\cdot23$
$\frac{secx}{6tanx}$
$2x^4+x^3-8^2-x+6$
$2^2-21a+20$
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