$10+5x+3y-8-x$
$\frac{d}{dx}\sqrt{2x^2-23}\:at\:x=4$
$\left(6x^2y^3-4xy^2\right)^2$
$2y''+\left(x+1\right)y'+3y$
$-4x-12>8$
$\int_1^2\left(4x+4\right)dx$
$\int_{\frac{\pi}{2}}^{\frac{\pi}{2}}\frac{x^2\sin x}{1+x^6}dx$
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