$\int x^2\left(3x^3+7\right)^5dx$

$\lim_{x\to\infty}\left(\left(\frac{2x+4}{2x+1}\right)^{4x+1}\right)$

$\int_{-\infty}^{-1}x^{-\frac{17}{7}}dx$

$\tan^5\left(x\right)-9\tan\left(x\right)=0$

$5\left(3\right)\left(-2\right)^2$

$\frac{d}{dx}4^x$

$25\left(4x+3\right)^2$