$\lim_{x\to0}\left(\frac{e^x}{3x^2}\right)$
$\frac{x\left(x+3\right)}{x^2+3}$
$\int\frac{-6s^2+11s+9}{s^2\left(s+1\right)}ds$
$-0.75+\left|\left(\frac{\sqrt{16}}{\sqrt{25}}\right)-0.2\right|+\frac{2}{3}\cdot\left(\frac{1}{4}\right)^2$
$5x+13=7x-1$
$\lim_{x\to0}\left(\frac{\left(-x+3\right)^2-9}{-3x}\right)$
$\lim\:_{x\to\:1}\left(\frac{8x^{\frac{7}{4}}-5x^{\frac{4}{5}}-3}{x^2-1}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!