$\left(15^2\right)^2$
$\frac{1}{\sqrt{\left(16x^2+25\right)}}$
$5x\:-\:x\:+\:3x\:$
$y^2+3=x-y$
$\tan\left(4x\right)\left(\sec\left(4x\right)\right)^4$
$\frac{\left(3x^4-27\right)}{x+2}$
$\frac{2x^4-7x^3+7x^2-13}{x-2}$
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