$\frac{\left(x^2-4\right)\left(x-3\right)}{x^2-x-6}$

$\left(3y+2\right)\left(3y+6\right)$

$\frac{d}{dx}3x^2y-5\sqrt{y}=4x+5y^2-8$

$2\:x\left(3\sqrt[3]{x^2}\right)$

$2\cos^3\left(x\right)-\sqrt{3}\cos^2\left(x\right)=0$

$\left(\frac{1}{4}x-2y^2\right)^2$

$-10x^4+\:5x\:^3+20x^2$