$\frac{12x^3+20x^2+20x+16}{3x+2}$
$\frac{x^3-32x^2}{x-2}$
$1-\frac{tany}{1+tan\:y}$
$3-5\cdot4$
$-14-\left(-7\right)$
$\left(2x-7y\right)\left(4x^2+14xy+49y^2\right)$
$\left(2x\right)\left(+3\right)^2$
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