$5x^2y^3;\:x=2;\:y=-1$
$\cot^3x\tan x=\csc^2x-1$
$\int\left(8x^4\left(x^5-7\right)^6\right)dx$
$\sqrt{\sqrt{16x^{\frac{1}{4}}}}$
$cos^2x=sinx\left(cscx+sinx\right)$
$17^{-1}\cdot17^2$
$8\cdot\left(2+9\right)$
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