$3^2\cdot60^2$
$\left(2x^3+3x^2-3x\right)-\left(5x^2+4x-7\right)$
$3x+5<14$
$\left(3x-4\right)+\left(3x+2\right)\cdot6$
$18<4x+6$
$5\left(2\right)^2-2\left(5\cdot3\right)-3\left(1\right)$
$\left(x+7\right)\left(x+4\right)$
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