$0=6x-\frac{48}{x^2}$
$\left(3a+b\right)\left(9a^2-3ab+b^2\right)$
$x^2+6x-3=0$
$2k^2+5k+3=0$
$3x^2-6y$
$\int_1^3\left(\frac{1}{x^4\sqrt{x^2+3}}\right)dx$
$x^2-12x-37$
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