$\left(3x^2+4y^3\right)^4$
$\left(-31\right)-\left(-60\right)$
$-2\left(s-3\right)+17s$
$\int se2xcos2xdx$
$9\left(x\:-\:y\:+\:z\right)^2\:-\:4\left(x\:+\:y\:-\:z\right)^2$
$2x^2-14x+3=0$
$3\left(2a+3\right)\left(2a-3\right)$
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