$3x\ge9$
$\left(3x+\sqrt{2}y\:+z\right)^2$
$\frac{x-4}{x^2-2x-8}$
$2p^2-p+10=0$
$\frac{dz}{dx}=4x^3+y^2-4x^2+y^6+1$
$\frac{3x^3-5x^2+x-2}{x-1}$
$-2x+3\le11$
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