$3 x + 6 > 2 x + 12$
$3\frac{6}{x^2}$
$\int x\cdot\sqrt{3x^2-12}dx$
$x^2-3\left(x+1\right)\le-3x-3$
$-12d-15$
$\int\frac{1}{x\left(x^2+1\right)^2}\cdot dx$
$30\cdot5+3$
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