$x+6\le14$
$\int\frac{8}{\left(x^4+4\right)}dx$
$7\left(1+6x\right)$
$\frac{-2}{x-2}+\frac{x}{x-2}$
$\int\left(5x-1\right)e^{-x}dx$
$x^{2\:}+19x+12=\left(4x+3\right)\left(x+4\right)$
$x^3-9x^2+27-27$
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