$8x-3>7x+12$
$10x+8=8x+16$
$\frac{8x^2}{2x+1}$
$4\left(2m\right)$
$3x+8\le x+20$
$sec^2x-4tanx=-1$
$\left(-4\right)^8\cdot\left(-4\right)^{-5}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!