$a+2a+3a-6a$
$\frac{3x-6}{x+2}>\frac{1}{4}$
$\sqrt{\frac{5}{49}m^2}nf^2$
$4mn\:+\:2m\:+\:6mn\:-\:9n$
$\left(-1\right)^4\cdot\left(\frac{7}{4}\right)\cdot x^3\cdot\left(\frac{1}{x}\right)^4$
$2^2+9x^4+4$
$9d\cdot\left(5d-2l\right)$
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