$\left(3a-4b\right)\left(3a-4b\right)$
$\sec\left(x\right)^2+4$
$\left(-5-b\right)^{-\frac{2}{3}}=\frac{1}{\left(-5\text{-b}\right)^{\frac{2}{3}}}$
$5.3p+7.6+3.8p-4.3+2.4q-7.4$
$\sqrt[7]{x^{15}}$
$15ab+16b-7ab-12\:\:\:$
$x+9=13$
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