$6x-3x-2x+5x+x$
$\lim_{x\to0}\left(3\right)\sin\left(9\right)$
$\left(1-\cos\left(4x\right)\right)\left(4x^2\right)$
$\frac{2as-at-4cs+2ct}{as-2at-2cs+4ct}$
$6x^2a+7ax^2-9x+8y+9x-3xy-8y$
$7=-7$
$\left(3a-6\right)\left(3a-2\right)$
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