$\int\left(\text{tan x}+\text{cot x}\right)^2dx$
$\sqrt[3]{\frac{\left(6x^2+9x^3\right)}{10x^4+2x}}$
$m^2-m-1$
$9,\:692\:-\:-34,\:580\:=\:$
$11x-23<-3+6x$
$\left(4-7\right)\cdot\left(9-11\right)$
$3\left(x-5\right)+2\left(4x+3\right)$
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