$\left(x+2\right)^2\left(x-3\right)^2$
$x^4-37x^2+36$
$-2x-5-3x-6-4x$
$n-6=-2$
$f\left(x\right)=\left(5x^3-3x^2\right)\cdot\:\left(-4x^2+2\right)$
$5.7-39.4$
$\left(-5m+6\right)+\left(-m+5\right)$
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