$\left(2^2\right)^{10}$
$10\cdot11-4\cdot3$
$-58=-\frac{w}{6}$
$2^{10.3}\cdot0.7$
$f\left(x\right)=\left(342x^2\right)\left(12x+1\right)$
$-\frac{585}{45}$
$10x>0$
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