$6\left(y+1\right)=2\left(3y+3\right)$
$-100a^5-50a^4-25a^3$
$h\left(x\right)=\left(-2x^{-1}+2x^{-2}\right)^2$
$216-x^12$
$\frac{dx}{dt}=-\frac{x}{100+4t}$
$2\cdot2\cdot3$
$1+2+3+4+5+15$
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