$\int_0^1\left(\frac{\left(e^{-2x}-1\right)}{5x}\right)dx$
$\lim\:_{x\to\:\:\infty\:}\left(\frac{\left(x^3\right)}{\left(e^{2x}\right)}\right)$
$\left(4a+4\right)\left(4a+5\right)$
$\left(\:4r^3n^5\right)^4$
$4-6x-9x^2$
$8a^2b-20a^2bx-2a+5ax$
$\lim_{x\to5}\left(-9x^2-6x-9\right)$
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