$r^2-4r$
$\left(-2y\right)\left(8x+5y\right)$
$f\left(x\right)=-10x^4+4x$
$\frac{s}{\left(s+2\right)\left(s^2+4\right)}$
$\frac{a^{-9\:x\:a^5}}{a^{-1}}$
$\frac{8^5\cdot3^7\cdot5^4}{12^3}$
$yx^{4}=y^{\prime}\frac{x^{2}}{3}+2x^{7}$
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