$x^2+6x-40=0$
$ax^2+bx=0$
$-2x-5-3x-6-4x$
$\left(\frac{2}{3}m^2+\frac{7}{2}mn-n^2\right)+\left(\frac{3}{2}mn+8m^2-\frac{1}{9}n^2\right)$
$2x+3<3$
$\frac{2\sqrt{x^2-2x+1}-\sqrt{x^2-4x+4}}{x}$
$\sqrt{117}$
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