$\frac{dy}{dx}=\left(x+y-3\right)^2$
$\sqrt[4]{\left(x+y\right)^3}.\sqrt[12]{\left(x+y\right)^{-1}}.\sqrt[3]{\left(x+y\right)^4}$
$\left(x^2-x+1\right)^2$
$x^3+5x^2+5x-2$
$\frac{dy}{dx}\:=\:x\cdot e^{y-x}$
$\left(2m+\frac{3}{7}n^x\right)^3$
$\frac{d}{dx}t$
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