$\int dk$
$3x+3\le-1$
$\int\left(\frac{4x^2+3}{\left(x+8\right)^3}\right)dx$
$4x<600$
$16x^2+96x$
$\lim_{x\to0}\left(\frac{1-x^2}{x^2}\right)$
$\frac{dy}{dx}=\frac{x^3y^2}{\sqrt{x^4+1}}$
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