$4-\left(a^2\cos^2\left(x\right)-a^2\sin^2\left(x\right)\right)$
$\lim_{x\to\infty}\left(-x^te^{-x}\right)$
$\frac{8a^8}{2a^2}$
$2x+7>5+x$
$\lim_{x\to\infty}\left(\frac{6x^4-2x^2+5x}{3x-3x^2+3x^4}\right)$
$2x^4+x^2-4x-1+4^4-2x$
$du=g$
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