$\left(1^22\right)-3$
$\frac{24ab^3+28a^2b^4-60a^3b^5}{4ab^2}$
$\int_0^12x^2\cdot e^{2x^3+1}dx$
$2\:+\:x^2\:=1$
$x^2+10-25$
$48:6-3\cdot4+12:4$
$4-a=+-15$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!