$\sqrt{x^2}+7-4$

$4\left(1\right)+4\left(9x\right)$

$-4-1-3-7-5-6-2-9-1$

$\left(-3x^2y^{-3}\right)\left(-4xy^4\right)^2$

$-7x^2\:-\:x\:+\:6x\:+\:x^2$

$\left(3cos\left(x\right)+2sin\left(x\right)\right)^2+\left(2cos\left(x\right)-3sin\left(x\right)\right)^2$

$\frac{4x^2+2x+2}{\sqrt{x}}$