$\lim_{x\to0}\left(\tan\left(2x\right)\right)$
$\frac{10x}{x^2+7+6}$
$\frac{dy}{dx}=\frac{4xy}{ln\left(y\right)^6}$
$4x^8\cdot4x^8$
$\frac{cos\frac{\left(k+1\right)x}{2}sin\frac{kx}{2}}{sin\:\frac{x}{2}}+cos\left(k+1\right)x$
$4-3u=-8$
$158.900+129.200$
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