$\frac{\left(3a^4\right)^5}{4a}$
$18x+8$
$\left(m^2+1\right)^3$
$\frac{dy}{dx}=\frac{-2x\left(3+y\right)}{x^2-4}$
$\int4x^{2}\sec^{2}\left(5x^{3}+2\right)dx$
$425-353-15-1$
$-770\:+\:-966$
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