$x\left(x^2+4\right)$
$\int\left(6x\cdot\cos\left(3x^2-1\right)\right)dx$
$m^2-4m-4$
$z^3-27$
$-52+190+-156+51+-2545+-654$
$\left(x^3+3y\right)\left(y^3+3y\right)$
$x^{x-4}=y$
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