$\left(1\right)^3-3\left(1\right)^2+4\left(1\right)-2$
$\quad\left(a-4\right)\left(a-6\right)$
$350\:-28$
$3x^2-2x^3x$
$x^4+2x^3+x^2$
$\frac{d}{dx}\left(\:x^3+y^3=6x^2y-9+2^{\frac{3}{2}}\right)$
$y=\frac{\left(x+11\right)}{\left(x^3-4\right)}$
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