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Exercise

$\left(0.003-x\right)^2$
1

A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$

${\left(3\times 10^{-3}\right)}^2-6\times 10^{-3}x+x^2$

Final answer to the exercise

${\left(3\times 10^{-3}\right)}^2-6\times 10^{-3}x+x^2$

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