$c2+4c+4=0$

$\frac{-2\sin\:^2\left(x\right)+1}{\sin\:\:x-\cos\:\:x}=-\left(\sin\:\left(x\right)+\cos\:\left(x\right)\right)$

$16a^2-\:25b^4$

$\frac{dy}{dt}=y\:+t^2+\sin\left(t\right)$

$49b^2-16$

$\int\:\frac{e^{4x}+4e^{2x}+1}{\left(e^{2x}+1\right)^2}dx$

$\frac{dy}{dx}=\frac{\sin\:\left(x\right)}{1+\sin\:\left(y\right)}$