$\left(x-6n\right)^3$
$49a^6-28a^3b^2+4b^4$
$\left(4x^2-3x\right)^2\cdot\left(5x^7+4x^{\frac{1}{2}}\right)^3$
$\left(tan^2x\right)\left(\frac{1}{sec^2x}\right)+\frac{1}{\sin\left(x\right)}$
$18=5m+3$
$-x+11=x+1$
$-\frac{1}{5}xy+\frac{4}{5}xy$
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