$\left(b+6\right)^2$
$\left(\tan y+\cot\left(y\right)\right)\:\sin\left(y\right)\cos\left(y\right)$
$\tan\left(y\right)dx+\left(1-x^2\right)dy=0$
$-x^3+2x^2+9x-18$
$x^4-5x^3+5x^2+5x-6$
$x-1=1$
$\frac{8x^2+6x-12}{x+4}$
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