$\frac{16y^7-24y^5+40y^4}{8y^2}$
$2x^6-x$
$-5x^2+x-3+x^2+2x^4+2$
$\frac{d^3}{dx^3}\left(\frac{1}{x-1}\right)$
$\left(-5x^2-4x-6\right)$
$-322\:-\:2$
$\frac{10}{10}\cdot450.000$
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